微软认证sql考试练习试题及答案
第1题
公司在数据库中存储供应商和价格信息。数据库中的所有商品都有牌价(list price)。 你需要只将供应商Fabrikam的所有产品的牌价提高20.00。应使用哪个查询?
A. UPDATE uct SET ListPrice = ListPrice + 20.00 WHERE NOT EXISTS ( SELECT VendorId FROM or WHERE VendorName = ’Fabrikam’);
B. UPDATE uct SET ListPrice = ListPrice + 20.00 WHERE VendorId NOT IN ( SELECT VendorId FROM or WHERE VendorName = ’Fabrikam’);
C. UPDATE uct SET ListPrice = ListPrice + 20.00 WHERE EXISTS ( SELECT VendorId FROM or WHERE VendorName = ’Fabrikam’);
D. UPDATE uct SET ListPrice = ListPrice + 20.00 WHERE VendorId IN (SELECT VendorId FROM or WHERE VendorName = ’Fabrikam’);
答案：D
第2题
你有名为Customer和SalesOrder的两个表。 你需要找出尚未采购任何东西的所有客户， 以及那些订单总额 (OrderTotal) 不到100的客户。应使用哪个查询?
A. SELECT * FROM Customer WHERE 100 > ALL ( SELECT OrderTotal FROM SalesOrder WHERE omerID = omerID)
B. SELECT * FROM Customer WHERE 100 > SOME ( SELECT OrderTotal FROM SalesOrder WHERE omerID = omerID)
C. SELECT * FROM Customer WHERE 100 > ( SELECT MAX(OrderTotal) FROM SalesOrder WHERE omerID = omerID)
D. SELECT * FROM Customer WHERE EXISTS ( SELECT omerID FROM SalesOrder WHERE omerID = omerID AND rTotal <= 100)
答案：A
第3题
你有名为Customer和SalesOrder的两个表。Customer表中有1000个客户，SalesOrder表中有其中900个客户的订单。你 执行下面的查询来列出至少有一笔销售的所有客户。 SELECT * FROM Customer WHERE omerID IN (SELECT omerID FROM SalesOrder)
你需要确定查询的结果。该查询应返回什么结果?
A. 没有行
B. 警告消息
C. Customer表中的.1000行
D. Customer表中与SalesOrder表中的行匹配的900行。
答案：C
第4题
Customer表中有下面的行：CustomerId Status 1 Active 2 Active 3 Inactive 4 NULL 5 Dormant 6 Dormant 你编写了下面 的查询来返回状态不为NULL或“Dormant”的所有客户： SELECT * FROM Customer WHERE Status NOT IN (NULL, ’Dormant’) 你需要确定查询的结果。你预计应出现哪个结果?
A. CustomerId Status
B. CustomerId Status 1 Active 2 Active 3 Inactive
C. CustomerId Status 1 Active 2 Active 3 Inactive 4 NULL
D. CustomerId Status 1 Active 2 Active 3 Inactive 4 NULL 5 Dormant 6 Dormant
答案：B
第5题
你有一个名为Employee的表。 你将每个员工的经理EmployeeID插入ReportsTo列来记录公司的组织层次结构。你需要 编写递归查询来生成员工及其经理的列表。 该查询还必须包含员工在层次结构中的级别。 你编写了下面的代码片段。 (包含的行号仅供参考。) 01 WITH EmployeeList (EmployeeID, FullName, ManagerName, Level)02 AS (03 ......... 04 )05 SELECT EmployeeID, FullName, ManagerName, Level06 FROM EmployeeList; 应在第3行插入哪一个代码片段?
A. SELECT EmployeeID, FullName, ’’ AS [ReportsTo], 1 AS [Level] FROM Employee WHERE ReportsTo IS NULL UNION ALL SELECT oyeeID, NName, Name, 1 + 1 AS [Level] FROM Employee emp JOIN Employee mgr ON rtsTo = oyeeID
B. SELECT EmployeeID, FullName, ’’ AS [ReportsTo], 1 AS [Level] FROM Employee WHERE ReportsTo IS NULL UNION ALL SELECT oyeeID, Name, Name, l + 1 FROM EmployeeList mgr JOIN Employee emp ON rtsTo = oyeeId
C. SELECT EmployeeID, FullName, ’’ AS [Reports To], 1 AS [Level] FROM Employee UNION ALL SELECT oyeeID, Name, Name, 1 + 1 AS [Level] FROM Employee emp LEFT JOIN Employee mgr ON rtsTo = oyeeID
D. SELECT EmployeeID, FullName, ’’ AS [ReportsTo], 1 AS [Level] FROM Employee UNION ALL SELECT oyeeID, Name, Name, l + 1 FROM EmployeeList mgr JOIN Employee emp ON rtsTo = oyeeID
答案：B
